Foot-Pound to Newton-Centimeter Converter
Foot-Pound to Newton-Centimeter Reference Table
| Foot-Pound (ft·lb) | Newton-Centimeter (N·cm) |
|---|---|
| 1 | 135.582 |
| 2 | 271.164 |
| 5 | 677.909 |
| 10 | 1355.82 |
| 20 | 2711.64 |
| 50 | 6779.09 |
| 100 | 13558.2 |
| 500 | 67790.9 |
| 1000 | 135582 |
Convert Foot-Pound to Newton-Centimeter instantly with our free online converter. The Foot-Pound (ft·lb) is equal to 1.35582 N·m — the standard torque unit in US automotive manuals for lug nuts, cylinder heads, and structural bolts. The Newton-Centimeter (N·cm) is equal to 0.01 N·m — used for miniature fasteners, electronics assembly, and precision instrument specifications. 1 Foot-Pound equals 135.582 Newton-Centimeter. To convert Foot-Pound to Newton-Centimeter, multiply the value by 135.582.
Frequently Asked Questions
How many Newton-Centimeters are in 1 Foot-Pound?
1 Foot-Pound equals 135.582 Newton-Centimeter. To convert Foot-Pound to Newton-Centimeter, multiply the value by 135.582.
How do you convert Foot-Pound to Newton-Centimeter?
To convert Foot-Pound to Newton-Centimeter, multiply the value by 135.582. For example, 10 ft·lb = 1355.82 N·cm.
What is a Foot-Pound used for?
The Foot-Pound (ft·lb) is equal to 1.35582 N·m — the standard torque unit in US automotive manuals for lug nuts, cylinder heads, and structural bolts.
What is a Newton-Centimeter used for?
The Newton-Centimeter (N·cm) is equal to 0.01 N·m — used for miniature fasteners, electronics assembly, and precision instrument specifications.
What is 100 Foot-Pound in Newton-Centimeter?
100 ft·lb equals 13558.2 N·cm. To convert Foot-Pound to Newton-Centimeter, multiply the value by 135.582.
What is a typical tightening torque for car wheel bolts?
Most passenger car wheel bolts require 100–130 Nm (74–96 ft-lb) of torque. Always check your vehicle's manual — overtightening can warp brake discs and crack wheel studs, while undertightening can cause wheels to loosen while driving. A calibrated torque wrench is essential for wheel changes.
How much torque does a car engine produce?
A typical compact car produces 150–250 Nm (110–184 ft-lb) of torque. Family sedans range from 250–400 Nm (184–295 ft-lb). High-performance sports cars can exceed 600 Nm (443 ft-lb). Diesel engines typically produce more torque than equivalent petrol engines, which is why diesels feel stronger at low revs.
What is the difference between Nm and ft-lb?
1 ft-lb (foot-pound) = 1.3558 Nm (newton-meters). 1 Nm = 0.7376 ft-lb. Newton-meters are the SI standard used in Europe and most of the world; foot-pounds are common in the US and UK automotive industry. To convert: multiply ft-lb by 1.356 to get Nm, or divide Nm by 1.356 to get ft-lb.
What torque is needed for common DIY tasks?
Spark plugs: 15–25 Nm. Oil drain plug: 20–40 Nm. Cylinder head bolts: 60–100 Nm (varies by engine). Bicycle pedals: 35–40 Nm. Furniture assembly bolts: 5–15 Nm. Always check manufacturer specs — torque requirements vary significantly between materials, thread sizes, and applications.
Why does torque matter more than power at low speeds?
Torque is the rotational force that actually moves a vehicle, while power is the rate at which work is done. At low speeds (pulling, accelerating from standstill), high torque is more useful — it determines how easily a vehicle can start moving or tow a load. Power (HP/kW) determines top speed and sustained high-speed performance. Diesel engines excel at towing due to high low-rpm torque.